tests: Adjust conformance tests to account for array invariant (#1289)

These were written before compiler optimizations and array invariant. It
is now impossible for t[1] to be stored in the hash part, as this would
violate the array invariant that says that elements 1..#t are stored in
the array.

For ipairs, it doesn't traverse the hash part anymore now, so we adjust
the code to make sure no elements outside of the 1..#t slice are
covered. For table.find, we can use find-with-offset to still access the
hash part.

Fixes #1283.
This commit is contained in:
Arseny Kapoulkine 2024-06-07 12:05:50 -05:00 committed by GitHub
parent 23b8726203
commit 81b2cc7dbe
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2 changed files with 5 additions and 6 deletions

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@ -726,16 +726,15 @@ assert((function()
return sum return sum
end)() == 15) end)() == 15)
-- the reason why this test is interesting is that the table created here has arraysize=0 and a single hash element with key = 1.0 -- ipairs will not iterate through hash part
-- ipairs must iterate through that
assert((function() assert((function()
local arr = { [1] = 42 } local arr = { [1] = 1, [42] = 42, x = 10 }
local sum = 0 local sum = 0
for i,v in ipairs(arr) do for i,v in ipairs(arr) do
sum = sum + v sum = sum + v
end end
return sum return sum
end)() == 42) end)() == 1)
-- the reason why this test is interesting is it ensures we do correct mutability analysis for locals -- the reason why this test is interesting is it ensures we do correct mutability analysis for locals
local function chainTest(n) local function chainTest(n)

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@ -412,8 +412,8 @@ do
assert(table.find({false, true}, true) == 2) assert(table.find({false, true}, true) == 2)
-- make sure table.find checks the hash portion as well by constructing a table literal that forces the value into the hash part -- make sure table.find checks the hash portion as well
assert(table.find({[(1)] = true}, true) == 1) assert(table.find({[(2)] = true}, true, 2) == 2)
end end
-- test table.concat -- test table.concat